First, we need to find the centripetal force acting on the car to maintain its circular motion on the incline. This force is provided by the friction force between the wheels and the road surface. The friction force can be calculated as:

Ff = µmgcosθ

where m is the mass of the car, g is the acceleration due to gravity, θ is the angle of the incline, and µ is the coefficient of friction.

In this case, θ = arctan(5%) = 2.86°. Substituting the given values, we get:

Ff = 0.5 x 2000 x 9.81 x cos(2.86°) = 964.5 N

The centripetal force required to maintain the circular motion can be calculated as:

Fc = mv^2/RL

where v is the speed of the car, and RL is the turning radius.

Substituting the given values, we get:

Fc = 2000 x (36/3.6)^2/RL = 20000/RL

Equating Fc and Ff, we get:

Fc = Ff

20000/RL = 964.5

RL = 20.8 m

Therefore, the turning radius of the car is 20.8 meters.