The correct answer is 162.

Let’s assume that the number of goals scored by P is x, and the number of goals scored by Q is y. According to the given information, the ratio of the number of goals by P to the number of goals by Q is 32, so we can write:

x/y = 32

Similarly, let’s assume that the number of goals scored by C is a, and the number of goals scored by R is b. According to the given information, the ratio of the number of goals by C to the number of goals by R is also 32, so we can write:

a/b = 32

We also know that the total number of goals scored in the matches is 342, so we can write:

x + y + a + b = 342

Now, we have three equations:

x/y = 32 a/b = 32 x + y + a + b = 342

To solve these equations, we can substitute the value of a/b from the second equation into the third equation:

x + y + (32b) + b = 342 x + y + 33b = 342

We can also substitute the value of x/y from the first equation into the third equation:

(32y) + y + 33b = 342 33y + 33b = 342

Now, we have two equations:

x + y + 33b = 342 33y + 33b = 342

We can subtract the second equation from the first equation to eliminate b:

(x + y + 33b) - (33y + 33b) = 342 - 342 x - 32y = 0 x = 32y

Now, we can substitute this value of x into the third equation:

(32y) + y + 33b = 342 33y + 33b = 342

We can divide both sides of this equation by 33 to simplify it:

y + b = 10

Since the ratio of the number of goals by P to the number of goals by Q is 32, we can substitute the value of x = 32y into the first equation:

x/y = 32 (32y)/y = 32 32 = 32

This equation is true for any value of y, so there are infinitely many solutions. However, we can find a specific solution by substituting the value of y = 3 into the equations:

x = 32y = 32(3) = 96 b = 10 - y = 10 - 3 = 7

Therefore, P scored 96 goals.