The area of a rhombus is given by the formula A = (d1 * d2) / 2, where d1 and d2 are the lengths of the diagonals.

Let’s assume that the diagonals of the rhombus are d1 and d2, and the altitude is h.

Since the diagonals of a rhombus bisect each other at right angles, we can divide the rhombus into four congruent right triangles.

The perimeter of the rhombus is given by the formula P = 4 * s, where s is the length of each side.

Since the diagonals of a rhombus bisect each other at right angles, we can use the Pythagorean theorem to find the length of each side.

Let’s assume that the length of each side is s.

Using the Pythagorean theorem, we have: s^2 = (d1/2)^2 + (h/2)^2 s^2 = (d2/2)^2 + (h/2)^2

Multiplying both sides of the equations by 4, we get: 4s^2 = d1^2 + h^2 4s^2 = d2^2 + h^2

Adding the two equations together, we get: 8s^2 = d1^2 + d2^2 + 2h^2

Since the perimeter of the rhombus is 28 m, we have: 4s = 28 s = 7

Substituting this value into the equation 8s^2 = d1^2 + d2^2 + 2h^2, we get: 8(7^2) = d1^2 + d2^2 + 2h^2 392 = d1^2 + d2^2 + 2h^2

Since the area of the rhombus is 56 m², we have: 56 = (d1 * d2) / 2 112 = d1 * d2

Now we have a system of equations: 392 = d1^2 + d2^2 + 2h^2 112 = d1 * d2

We can solve this system of equations to find the values of d1, d2, and h.

However, without additional information, it is not possible to determine the exact values of d1, d2, and h.